4(2x+1)=6(3x-2)

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Solution for 4(2x+1)=6(3x-2) equation: 



4(2x+1)=6(3x-2)

We move all terms to the left:

4(2x+1)-(6(3x-2))=0

We multiply parentheses

8x-(6(3x-2))+4=0



We calculate terms in parentheses: -(6(3x-2)), so:

6(3x-2)

We multiply parentheses

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

8x-18x+12+4=0

We add all the numbers together, and all the variables

-10x+16=0

We move all terms containing x to the left, all other terms to the right

-10x=-16

x=-16/-10

x=1+3/5

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