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4(2x+2)-2(x+2)=10-3(x+2)
We move all terms to the left:
4(2x+2)-2(x+2)-(10-3(x+2))=0
We multiply parentheses
8x-2x-(10-3(x+2))+8-4=0
We calculate terms in parentheses: -(10-3(x+2)), so:We add all the numbers together, and all the variables
10-3(x+2)
determiningTheFunctionDomain -3(x+2)+10
We multiply parentheses
-3x-6+10
We add all the numbers together, and all the variables
-3x+4
Back to the equation:
-(-3x+4)
6x-(-3x+4)+4=0
We get rid of parentheses
6x+3x-4+4=0
We add all the numbers together, and all the variables
9x=0
x=0/9
x=0
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