4(2x+2)-8=7(x-5)+2x

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Solution for 4(2x+2)-8=7(x-5)+2x equation: 



4(2x+2)-8=7(x-5)+2x

We move all terms to the left:

4(2x+2)-8-(7(x-5)+2x)=0

We multiply parentheses

8x-(7(x-5)+2x)+8-8=0



We calculate terms in parentheses: -(7(x-5)+2x), so:

7(x-5)+2x

We add all the numbers together, and all the variables

2x+7(x-5)

We multiply parentheses

2x+7x-35

We add all the numbers together, and all the variables

9x-35

Back to the equation:

-(9x-35)



We add all the numbers together, and all the variables

8x-(9x-35)=0

We get rid of parentheses

8x-9x+35=0

We add all the numbers together, and all the variables

-1x+35=0

We move all terms containing x to the left, all other terms to the right

-x=-35

x=-35/-1

x=+35

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