4(2x+2)=2x+22+3(2x+2)

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Solution for 4(2x+2)=2x+22+3(2x+2) equation: 



4(2x+2)=2x+22+3(2x+2)

We move all terms to the left:

4(2x+2)-(2x+22+3(2x+2))=0

We multiply parentheses

8x-(2x+22+3(2x+2))+8=0



We calculate terms in parentheses: -(2x+22+3(2x+2)), so:

2x+22+3(2x+2)

determiningTheFunctionDomain
2x+3(2x+2)+22

We multiply parentheses

2x+6x+6+22

We add all the numbers together, and all the variables

8x+28

Back to the equation:

-(8x+28)



We get rid of parentheses

8x-8x-28+8=0

We add all the numbers together, and all the variables

-20!=0

There is no solution for this equation

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