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4(2x+2)=5(2x+1)-5
We move all terms to the left:
4(2x+2)-(5(2x+1)-5)=0
We multiply parentheses
8x-(5(2x+1)-5)+8=0
We calculate terms in parentheses: -(5(2x+1)-5), so:We add all the numbers together, and all the variables
5(2x+1)-5
We multiply parentheses
10x+5-5
We add all the numbers together, and all the variables
10x
Back to the equation:
-(10x)
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4
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