4(2x+3)(2x+3)=0

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Solution for 4(2x+3)(2x+3)=0 equation: 



4(2x+3)(2x+3)=0

We multiply parentheses ..

4(+4x^2+6x+6x+9)=0

We multiply parentheses

16x^2+24x+24x+36=0

We add all the numbers together, and all the variables

16x^2+48x+36=0

a = 16; b = 48; c = +36;
Δ = b2-4ac
Δ = 482-4·16·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-48}{32}=-1+1/2$

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