4(2x+3)+2(3x-2)=36

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Solution for 4(2x+3)+2(3x-2)=36 equation: 



4(2x+3)+2(3x-2)=36

We move all terms to the left:

4(2x+3)+2(3x-2)-(36)=0

We multiply parentheses

8x+6x+12-4-36=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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