4(2x+3)+2(3x-4=3x-x+40

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Solution for 4(2x+3)+2(3x-4=3x-x+40 equation: 



4(2x+3)+2(3x-4=3x-x+40

We move all terms to the left:

4(2x+3)+2(3x-4-(3x-x+40)=0

We add all the numbers together, and all the variables

4(2x+3)+2(3x-4-(2x+40)=0

We multiply parentheses

8x+2(3x-4-(2x+40)+12=0

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