4(2x+3)-(8x-4)=16

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Solution for 4(2x+3)-(8x-4)=16 equation: 



4(2x+3)-(8x-4)=16

We move all terms to the left:

4(2x+3)-(8x-4)-(16)=0

We multiply parentheses

8x-(8x-4)+12-16=0

We get rid of parentheses

8x-8x+4+12-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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