4(2x+3)-2(3x-3)+12=3(2x+5)+20

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Solution for 4(2x+3)-2(3x-3)+12=3(2x+5)+20 equation: 



4(2x+3)-2(3x-3)+12=3(2x+5)+20

We move all terms to the left:

4(2x+3)-2(3x-3)+12-(3(2x+5)+20)=0

We multiply parentheses

8x-6x-(3(2x+5)+20)+12+6+12=0



We calculate terms in parentheses: -(3(2x+5)+20), so:

3(2x+5)+20

We multiply parentheses

6x+15+20

We add all the numbers together, and all the variables

6x+35

Back to the equation:

-(6x+35)



We add all the numbers together, and all the variables

2x-(6x+35)+30=0

We get rid of parentheses

2x-6x-35+30=0

We add all the numbers together, and all the variables

-4x-5=0

We move all terms containing x to the left, all other terms to the right

-4x=5

x=5/-4

x=-1+1/4

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