4(2x+3)-2(3x-4)=16

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Solution for 4(2x+3)-2(3x-4)=16 equation: 



4(2x+3)-2(3x-4)=16

We move all terms to the left:

4(2x+3)-2(3x-4)-(16)=0

We multiply parentheses

8x-6x+12+8-16=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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