4(2x+3)-3(x+3)=2(3x-2)+(x+3)

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Solution for 4(2x+3)-3(x+3)=2(3x-2)+(x+3) equation: 



4(2x+3)-3(x+3)=2(3x-2)+(x+3)

We move all terms to the left:

4(2x+3)-3(x+3)-(2(3x-2)+(x+3))=0

We multiply parentheses

8x-3x-(2(3x-2)+(x+3))+12-9=0



We calculate terms in parentheses: -(2(3x-2)+(x+3)), so:

2(3x-2)+(x+3)

We multiply parentheses

6x+(x+3)-4

We get rid of parentheses

6x+x+3-4

We add all the numbers together, and all the variables

7x-1

Back to the equation:

-(7x-1)



We add all the numbers together, and all the variables

5x-(7x-1)+3=0

We get rid of parentheses

5x-7x+1+3=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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