4(2x+3)-x=3x-2(6-x)

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Solution for 4(2x+3)-x=3x-2(6-x) equation: 



4(2x+3)-x=3x-2(6-x)

We move all terms to the left:

4(2x+3)-x-(3x-2(6-x))=0

We add all the numbers together, and all the variables

4(2x+3)-x-(3x-2(-1x+6))=0

We add all the numbers together, and all the variables

-1x+4(2x+3)-(3x-2(-1x+6))=0

We multiply parentheses

-1x+8x-(3x-2(-1x+6))+12=0



We calculate terms in parentheses: -(3x-2(-1x+6)), so:

3x-2(-1x+6)

We multiply parentheses

3x+2x-12

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We add all the numbers together, and all the variables

7x-(5x-12)+12=0

We get rid of parentheses

7x-5x+12+12=0

We add all the numbers together, and all the variables

2x+24=0

We move all terms containing x to the left, all other terms to the right

2x=-24

x=-24/2

x=-12

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