4(2x+3)=(2x-2)+(3x+7)

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Solution for 4(2x+3)=(2x-2)+(3x+7) equation: 



4(2x+3)=(2x-2)+(3x+7)

We move all terms to the left:

4(2x+3)-((2x-2)+(3x+7))=0

We multiply parentheses

8x-((2x-2)+(3x+7))+12=0



We calculate terms in parentheses: -((2x-2)+(3x+7)), so:

(2x-2)+(3x+7)

We get rid of parentheses

2x+3x-2+7

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We get rid of parentheses

8x-5x-5+12=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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