4(2x+3)=(2x-2)+2(3x-7)

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Solution for 4(2x+3)=(2x-2)+2(3x-7) equation: 



4(2x+3)=(2x-2)+2(3x-7)

We move all terms to the left:

4(2x+3)-((2x-2)+2(3x-7))=0

We multiply parentheses

8x-((2x-2)+2(3x-7))+12=0



We calculate terms in parentheses: -((2x-2)+2(3x-7)), so:

(2x-2)+2(3x-7)

We multiply parentheses

(2x-2)+6x-14

We get rid of parentheses

2x+6x-2-14

We add all the numbers together, and all the variables

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

8x-8x+16+12=0

We add all the numbers together, and all the variables

28!=0

There is no solution for this equation

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