4(2x+3)=(x-1)+31

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Solution for 4(2x+3)=(x-1)+31 equation: 



4(2x+3)=(x-1)+31

We move all terms to the left:

4(2x+3)-((x-1)+31)=0

We multiply parentheses

8x-((x-1)+31)+12=0



We calculate terms in parentheses: -((x-1)+31), so:

(x-1)+31

We get rid of parentheses

x-1+31

We add all the numbers together, and all the variables

x+30

Back to the equation:

-(x+30)



We get rid of parentheses

8x-x-30+12=0

We add all the numbers together, and all the variables

7x-18=0

We move all terms containing x to the left, all other terms to the right

7x=18

x=18/7

x=2+4/7

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