4(2x+3)=3(4x+8/3)

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Solution for 4(2x+3)=3(4x+8/3) equation: 



4(2x+3)=3(4x+8/3)

We move all terms to the left:

4(2x+3)-(3(4x+8/3))=0

We add all the numbers together, and all the variables

4(2x+3)-(3(+4x+8/3))=0

We multiply parentheses

8x-(3(+4x+8/3))+12=0

We multiply all the terms by the denominator


8x*3))-(3(+4x+8+12*3))=0

We add all the numbers together, and all the variables

8x*3))-(3(4x+44))=0

We add all the numbers together, and all the variables

8x*3))-(3(4x=0

Wy multiply elements

24x^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{48}=0$

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