4(2x+3)=3(x+1)+31

Solution for 4(2x+3)=3(x+1)+31 equation:

4(2x+3)=3(x+1)+31

We move all terms to the left:

4(2x+3)-(3(x+1)+31)=0

We multiply parentheses

8x-(3(x+1)+31)+12=0


We calculate terms in parentheses: -(3(x+1)+31), so:

3(x+1)+31

We multiply parentheses

3x+3+31

We add all the numbers together, and all the variables

3x+34

Back to the equation:

-(3x+34)


We get rid of parentheses

8x-3x-34+12=0

We add all the numbers together, and all the variables

5x-22=0

We move all terms containing x to the left, all other terms to the right

5x=22

x=22/5

x=4+2/5