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4(2x+3)=36+4(2x-2)
We move all terms to the left:
4(2x+3)-(36+4(2x-2))=0
We multiply parentheses
8x-(36+4(2x-2))+12=0
We calculate terms in parentheses: -(36+4(2x-2)), so:We get rid of parentheses
36+4(2x-2)
determiningTheFunctionDomain 4(2x-2)+36
We multiply parentheses
8x-8+36
We add all the numbers together, and all the variables
8x+28
Back to the equation:
-(8x+28)
8x-8x-28+12=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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