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4(2x+3)=6-(x-2)
We move all terms to the left:
4(2x+3)-(6-(x-2))=0
We multiply parentheses
8x-(6-(x-2))+12=0
We calculate terms in parentheses: -(6-(x-2)), so:We get rid of parentheses
6-(x-2)
determiningTheFunctionDomain -(x-2)+6
We get rid of parentheses
-x+2+6
We add all the numbers together, and all the variables
-1x+8
Back to the equation:
-(-1x+8)
8x+1x-8+12=0
We add all the numbers together, and all the variables
9x+4=0
We move all terms containing x to the left, all other terms to the right
9x=-4
x=-4/9
x=-4/9
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