4(2x+3)=7x+19

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Solution for 4(2x+3)=7x+19 equation: 



4(2x+3)=7x+19

We move all terms to the left:

4(2x+3)-(7x+19)=0

We multiply parentheses

8x-(7x+19)+12=0

We get rid of parentheses

8x-7x-19+12=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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