4(2x+3)=8+2(3x+5)

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Solution for 4(2x+3)=8+2(3x+5) equation: 



4(2x+3)=8+2(3x+5)

We move all terms to the left:

4(2x+3)-(8+2(3x+5))=0

We multiply parentheses

8x-(8+2(3x+5))+12=0



We calculate terms in parentheses: -(8+2(3x+5)), so:

8+2(3x+5)

determiningTheFunctionDomain
2(3x+5)+8

We multiply parentheses

6x+10+8

We add all the numbers together, and all the variables

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

8x-6x-18+12=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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