4(2x+4)+3=2(6x-4)-23

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Solution for 4(2x+4)+3=2(6x-4)-23 equation: 



4(2x+4)+3=2(6x-4)-23

We move all terms to the left:

4(2x+4)+3-(2(6x-4)-23)=0

We multiply parentheses

8x-(2(6x-4)-23)+16+3=0



We calculate terms in parentheses: -(2(6x-4)-23), so:

2(6x-4)-23

We multiply parentheses

12x-8-23

We add all the numbers together, and all the variables

12x-31

Back to the equation:

-(12x-31)



We add all the numbers together, and all the variables

8x-(12x-31)+19=0

We get rid of parentheses

8x-12x+31+19=0

We add all the numbers together, and all the variables

-4x+50=0

We move all terms containing x to the left, all other terms to the right

-4x=-50

x=-50/-4

x=12+1/2

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