4(2x+4)+6(x-5)=70

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Solution for 4(2x+4)+6(x-5)=70 equation: 



4(2x+4)+6(x-5)=70

We move all terms to the left:

4(2x+4)+6(x-5)-(70)=0

We multiply parentheses

8x+6x+16-30-70=0

We add all the numbers together, and all the variables

14x-84=0

We move all terms containing x to the left, all other terms to the right

14x=84

x=84/14

x=6

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