4(2x+4)-2(x-3)=8(2x+4)

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Solution for 4(2x+4)-2(x-3)=8(2x+4) equation: 



4(2x+4)-2(x-3)=8(2x+4)

We move all terms to the left:

4(2x+4)-2(x-3)-(8(2x+4))=0

We multiply parentheses

8x-2x-(8(2x+4))+16+6=0



We calculate terms in parentheses: -(8(2x+4)), so:

8(2x+4)

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We add all the numbers together, and all the variables

6x-(16x+32)+22=0

We get rid of parentheses

6x-16x-32+22=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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