4(2x+5)+3(x+3)=(x-1)

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Solution for 4(2x+5)+3(x+3)=(x-1) equation: 



4(2x+5)+3(x+3)=(x-1)

We move all terms to the left:

4(2x+5)+3(x+3)-((x-1))=0

We multiply parentheses

8x+3x-((x-1))+20+9=0



We calculate terms in parentheses: -((x-1)), so:

(x-1)

We get rid of parentheses

x-1

Back to the equation:

-(x-1)



We add all the numbers together, and all the variables

11x-(x-1)+29=0

We get rid of parentheses

11x-x+1+29=0

We add all the numbers together, and all the variables

10x+30=0

We move all terms containing x to the left, all other terms to the right

10x=-30

x=-30/10

x=-3

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