4(2x+5)+3(x-4)=41

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Solution for 4(2x+5)+3(x-4)=41 equation: 



4(2x+5)+3(x-4)=41

We move all terms to the left:

4(2x+5)+3(x-4)-(41)=0

We multiply parentheses

8x+3x+20-12-41=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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