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4(2x+5)-3x=4(x+3)+x
We move all terms to the left:
4(2x+5)-3x-(4(x+3)+x)=0
We add all the numbers together, and all the variables
-3x+4(2x+5)-(4(x+3)+x)=0
We multiply parentheses
-3x+8x-(4(x+3)+x)+20=0
We calculate terms in parentheses: -(4(x+3)+x), so:We add all the numbers together, and all the variables
4(x+3)+x
We add all the numbers together, and all the variables
x+4(x+3)
We multiply parentheses
x+4x+12
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
5x-(5x+12)+20=0
We get rid of parentheses
5x-5x-12+20=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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