4(2x+5)=1/2(12x+28)

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Solution for 4(2x+5)=1/2(12x+28) equation: 



4(2x+5)=1/2(12x+28)

We move all terms to the left:

4(2x+5)-(1/2(12x+28))=0



Domain of the equation: 2(12x+28))!=0

x∈R



We multiply parentheses

8x-(1/2(12x+28))+20=0

We multiply all the terms by the denominator


8x*2(12x+28))-(1+20*2(12x+28))=0

Wy multiply elements

16x^2(1+40x(1=0

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