4(2x+5)=x+27

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Solution for 4(2x+5)=x+27 equation:



4(2x+5)=x+27
We move all terms to the left:
4(2x+5)-(x+27)=0
We multiply parentheses
8x-(x+27)+20=0
We get rid of parentheses
8x-x-27+20=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1

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