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4(2x+7)(x-10)=0
We multiply parentheses ..
4(+2x^2-20x+7x-70)=0
We multiply parentheses
8x^2-80x+28x-280=0
We add all the numbers together, and all the variables
8x^2-52x-280=0
a = 8; b = -52; c = -280;
Δ = b2-4ac
Δ = -522-4·8·(-280)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-108}{2*8}=\frac{-56}{16} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+108}{2*8}=\frac{160}{16} =10 $
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