4(2x+8)=3(x+4)+2(x-3)

Solution for 4(2x+8)=3(x+4)+2(x-3) equation:

4(2x+8)=3(x+4)+2(x-3)

We move all terms to the left:

4(2x+8)-(3(x+4)+2(x-3))=0

We multiply parentheses

8x-(3(x+4)+2(x-3))+32=0


We calculate terms in parentheses: -(3(x+4)+2(x-3)), so:

3(x+4)+2(x-3)

We multiply parentheses

3x+2x+12-6

We add all the numbers together, and all the variables

5x+6

Back to the equation:

-(5x+6)


We get rid of parentheses

8x-5x-6+32=0

We add all the numbers together, and all the variables

3x+26=0

We move all terms containing x to the left, all other terms to the right

3x=-26

x=-26/3

x=-8+2/3