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4(2x+9)5x=-3
We move all terms to the left:
4(2x+9)5x-(-3)=0
We add all the numbers together, and all the variables
4(2x+9)5x+3=0
We multiply parentheses
40x^2+180x+3=0
a = 40; b = 180; c = +3;
Δ = b2-4ac
Δ = 1802-4·40·3
Δ = 31920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31920}=\sqrt{16*1995}=\sqrt{16}*\sqrt{1995}=4\sqrt{1995}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-4\sqrt{1995}}{2*40}=\frac{-180-4\sqrt{1995}}{80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+4\sqrt{1995}}{2*40}=\frac{-180+4\sqrt{1995}}{80} $
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