4(2x-1)+12=6-3(x-4)

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Solution for 4(2x-1)+12=6-3(x-4) equation:



4(2x-1)+12=6-3(x-4)
We move all terms to the left:
4(2x-1)+12-(6-3(x-4))=0
We multiply parentheses
8x-(6-3(x-4))-4+12=0
We calculate terms in parentheses: -(6-3(x-4)), so:
6-3(x-4)
determiningTheFunctionDomain -3(x-4)+6
We multiply parentheses
-3x+12+6
We add all the numbers together, and all the variables
-3x+18
Back to the equation:
-(-3x+18)
We add all the numbers together, and all the variables
8x-(-3x+18)+8=0
We get rid of parentheses
8x+3x-18+8=0
We add all the numbers together, and all the variables
11x-10=0
We move all terms containing x to the left, all other terms to the right
11x=10
x=10/11
x=10/11

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