4(2x-1)+2=8(x+2)-x

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Solution for 4(2x-1)+2=8(x+2)-x equation: 



4(2x-1)+2=8(x+2)-x

We move all terms to the left:

4(2x-1)+2-(8(x+2)-x)=0

We multiply parentheses

8x-(8(x+2)-x)-4+2=0



We calculate terms in parentheses: -(8(x+2)-x), so:

8(x+2)-x

We add all the numbers together, and all the variables

-1x+8(x+2)

We multiply parentheses

-1x+8x+16

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

8x-(7x+16)-2=0

We get rid of parentheses

8x-7x-16-2=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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