4(2x-1)+5(5x+10)+2(10x-4)+2(11x+20)=2

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Solution for 4(2x-1)+5(5x+10)+2(10x-4)+2(11x+20)=2 equation: 



4(2x-1)+5(5x+10)+2(10x-4)+2(11x+20)=2

We move all terms to the left:

4(2x-1)+5(5x+10)+2(10x-4)+2(11x+20)-(2)=0

We multiply parentheses

8x+25x+20x+22x-4+50-8+40-2=0

We add all the numbers together, and all the variables

75x+76=0

We move all terms containing x to the left, all other terms to the right

75x=-76

x=-76/75

x=-1+1/75

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