4(2x-1)+8=3(2+x)-62

Solution for 4(2x-1)+8=3(2+x)-62 equation:

4(2x-1)+8=3(2+x)-62

We move all terms to the left:

4(2x-1)+8-(3(2+x)-62)=0

We add all the numbers together, and all the variables

4(2x-1)-(3(x+2)-62)+8=0

We multiply parentheses

8x-(3(x+2)-62)-4+8=0


We calculate terms in parentheses: -(3(x+2)-62), so:

3(x+2)-62

We multiply parentheses

3x+6-62

We add all the numbers together, and all the variables

3x-56

Back to the equation:

-(3x-56)


We add all the numbers together, and all the variables

8x-(3x-56)+4=0

We get rid of parentheses

8x-3x+56+4=0

We add all the numbers together, and all the variables

5x+60=0

We move all terms containing x to the left, all other terms to the right

5x=-60

x=-60/5

x=-12