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4(2x-1)-(3x+1)=2(x-4)
We move all terms to the left:
4(2x-1)-(3x+1)-(2(x-4))=0
We multiply parentheses
8x-(3x+1)-(2(x-4))-4=0
We get rid of parentheses
8x-3x-(2(x-4))-1-4=0
We calculate terms in parentheses: -(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
5x-(2x-8)-5=0
We get rid of parentheses
5x-2x+8-5=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1
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