4(2x-1)-(3x+1)=2(x-4)

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Solution for 4(2x-1)-(3x+1)=2(x-4) equation: 



4(2x-1)-(3x+1)=2(x-4)

We move all terms to the left:

4(2x-1)-(3x+1)-(2(x-4))=0

We multiply parentheses

8x-(3x+1)-(2(x-4))-4=0

We get rid of parentheses

8x-3x-(2(x-4))-1-4=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

5x-(2x-8)-5=0

We get rid of parentheses

5x-2x+8-5=0

We add all the numbers together, and all the variables

3x+3=0

We move all terms containing x to the left, all other terms to the right

3x=-3

x=-3/3

x=-1

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