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4(2x-1)-2(x-5)5(x+1)+3=0
We multiply parentheses
8x-2(x-5)5(x+1)-4+3=0
We add all the numbers together, and all the variables
8x-2(x-5)5(x+1)-1=0
We move all terms containing x to the left, all other terms to the right
8x-2(x-5)5(x+1)=1
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