4(2x-10)-3=4(x-5)+(1)

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Solution for 4(2x-10)-3=4(x-5)+(1) equation: 



4(2x-10)-3=4(x-5)+(1)

We move all terms to the left:

4(2x-10)-3-(4(x-5)+(1))=0

We multiply parentheses

8x-(4(x-5)+1)-40-3=0



We calculate terms in parentheses: -(4(x-5)+1), so:

4(x-5)+1

We multiply parentheses

4x-20+1

We add all the numbers together, and all the variables

4x-19

Back to the equation:

-(4x-19)



We add all the numbers together, and all the variables

8x-(4x-19)-43=0

We get rid of parentheses

8x-4x+19-43=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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