4(2x-10)=8(x-5)

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Solution for 4(2x-10)=8(x-5) equation:


Simplifying
4(2x + -10) = 8(x + -5)

Reorder the terms:
4(-10 + 2x) = 8(x + -5)
(-10 * 4 + 2x * 4) = 8(x + -5)
(-40 + 8x) = 8(x + -5)

Reorder the terms:
-40 + 8x = 8(-5 + x)
-40 + 8x = (-5 * 8 + x * 8)
-40 + 8x = (-40 + 8x)

Add '40' to each side of the equation.
-40 + 40 + 8x = -40 + 40 + 8x

Combine like terms: -40 + 40 = 0
0 + 8x = -40 + 40 + 8x
8x = -40 + 40 + 8x

Combine like terms: -40 + 40 = 0
8x = 0 + 8x
8x = 8x

Add '-8x' to each side of the equation.
8x + -8x = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 8x + -8x

Combine like terms: 8x + -8x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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