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4(2x-11)6x=-3
We move all terms to the left:
4(2x-11)6x-(-3)=0
We add all the numbers together, and all the variables
4(2x-11)6x+3=0
We multiply parentheses
48x^2-264x+3=0
a = 48; b = -264; c = +3;
Δ = b2-4ac
Δ = -2642-4·48·3
Δ = 69120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{69120}=\sqrt{2304*30}=\sqrt{2304}*\sqrt{30}=48\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-264)-48\sqrt{30}}{2*48}=\frac{264-48\sqrt{30}}{96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-264)+48\sqrt{30}}{2*48}=\frac{264+48\sqrt{30}}{96} $
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