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4(2x-2)-2=5-(3x+4)
We move all terms to the left:
4(2x-2)-2-(5-(3x+4))=0
We multiply parentheses
8x-(5-(3x+4))-8-2=0
We calculate terms in parentheses: -(5-(3x+4)), so:We add all the numbers together, and all the variables
5-(3x+4)
determiningTheFunctionDomain -(3x+4)+5
We get rid of parentheses
-3x-4+5
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
8x-(-3x+1)-10=0
We get rid of parentheses
8x+3x-1-10=0
We add all the numbers together, and all the variables
11x-11=0
We move all terms containing x to the left, all other terms to the right
11x=11
x=11/11
x=1
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