4(2x-2)-5=4(x-2)+31

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Solution for 4(2x-2)-5=4(x-2)+31 equation: 



4(2x-2)-5=4(x-2)+31

We move all terms to the left:

4(2x-2)-5-(4(x-2)+31)=0

We multiply parentheses

8x-(4(x-2)+31)-8-5=0



We calculate terms in parentheses: -(4(x-2)+31), so:

4(x-2)+31

We multiply parentheses

4x-8+31

We add all the numbers together, and all the variables

4x+23

Back to the equation:

-(4x+23)



We add all the numbers together, and all the variables

8x-(4x+23)-13=0

We get rid of parentheses

8x-4x-23-13=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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