4(2x-2)=3(x-4)=57

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Solution for 4(2x-2)=3(x-4)=57 equation: 



4(2x-2)=3(x-4)=57

We move all terms to the left:

4(2x-2)-(3(x-4))=0

We multiply parentheses

8x-(3(x-4))-8=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

8x-3x+12-8=0

We add all the numbers together, and all the variables

5x+4=0

We move all terms containing x to the left, all other terms to the right

5x=-4

x=-4/5

x=-4/5

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