4(2x-2)=6(2+3x)

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Solution for 4(2x-2)=6(2+3x) equation: 



4(2x-2)=6(2+3x)

We move all terms to the left:

4(2x-2)-(6(2+3x))=0

We add all the numbers together, and all the variables

4(2x-2)-(6(3x+2))=0

We multiply parentheses

8x-(6(3x+2))-8=0



We calculate terms in parentheses: -(6(3x+2)), so:

6(3x+2)

We multiply parentheses

18x+12

Back to the equation:

-(18x+12)



We get rid of parentheses

8x-18x-12-8=0

We add all the numbers together, and all the variables

-10x-20=0

We move all terms containing x to the left, all other terms to the right

-10x=20

x=20/-10

x=-2

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