4(2x-2)=6(3x+12)

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Solution for 4(2x-2)=6(3x+12) equation: 



4(2x-2)=6(3x+12)

We move all terms to the left:

4(2x-2)-(6(3x+12))=0

We multiply parentheses

8x-(6(3x+12))-8=0



We calculate terms in parentheses: -(6(3x+12)), so:

6(3x+12)

We multiply parentheses

18x+72

Back to the equation:

-(18x+72)



We get rid of parentheses

8x-18x-72-8=0

We add all the numbers together, and all the variables

-10x-80=0

We move all terms containing x to the left, all other terms to the right

-10x=80

x=80/-10

x=-8

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