4(2x-2)=6(3x+2)x=

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Solution for 4(2x-2)=6(3x+2)x= equation: 



4(2x-2)=6(3x+2)x=

We move all terms to the left:

4(2x-2)-(6(3x+2)x)=0

We multiply parentheses

8x-(6(3x+2)x)-8=0



We calculate terms in parentheses: -(6(3x+2)x), so:

6(3x+2)x

We multiply parentheses

18x^2+12x

Back to the equation:

-(18x^2+12x)



We get rid of parentheses

-18x^2+8x-12x-8=0

We add all the numbers together, and all the variables

-18x^2-4x-8=0

a = -18; b = -4; c = -8;
Δ = b2-4ac
Δ = -42-4·(-18)·(-8)
Δ = -560
Delta is less than zero, so there is no solution for the equation

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