4(2x-3)+3x=3(x-12)

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Solution for 4(2x-3)+3x=3(x-12) equation: 



4(2x-3)+3x=3(x-12)

We move all terms to the left:

4(2x-3)+3x-(3(x-12))=0

We add all the numbers together, and all the variables

3x+4(2x-3)-(3(x-12))=0

We multiply parentheses

3x+8x-(3(x-12))-12=0



We calculate terms in parentheses: -(3(x-12)), so:

3(x-12)

We multiply parentheses

3x-36

Back to the equation:

-(3x-36)



We add all the numbers together, and all the variables

11x-(3x-36)-12=0

We get rid of parentheses

11x-3x+36-12=0

We add all the numbers together, and all the variables

8x+24=0

We move all terms containing x to the left, all other terms to the right

8x=-24

x=-24/8

x=-3

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