4(2x-3)+4(x-1)=8

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Solution for 4(2x-3)+4(x-1)=8 equation: 



4(2x-3)+4(x-1)=8

We move all terms to the left:

4(2x-3)+4(x-1)-(8)=0

We multiply parentheses

8x+4x-12-4-8=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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